First Fly Rod, Reel and line Questions??
 

On 3/8/06 11:39 AM, in article
et, "rw"
wrote:

rb608 wrote:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

pi feet

Isn't pi the constant?

My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to d
(which we had converted from feet to inches), we have C=pi(d+6). Balances
out with 6(pi). No?


Bill

First Fly Rod, Reel and line Questions??
 

On 3/8/06 11:53 AM, in article , "William
Claspy" wrote:

On 3/8/06 11:39 AM, in article
et, "rw"
wrote:

rb608 wrote:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

pi feet

Isn't pi the constant?

My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to d
(which we had converted from feet to inches), we have C=pi(d+6). Balances
out with 6(pi). No?

Whoops. He wanted 6" added to r. So make that 12"(pi), which is pi feet.

I'm a little slow on the uptake. (Narrow arbor :-)

Bill

First Fly Rod, Reel and line Questions??
 

"William Claspy" wrote in message
My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to d
(which we had converted from feet to inches), we have C=pi(d+6). Balances
out with 6(pi). No?

No. You're thinking correctly, but you only got halfway there. You're
actually increasing the diameter by a whole foot (6 inches each side).

Joe F.

First Fly Rod, Reel and line Questions??
 

"William Claspy" wrote in message
Whoops. He wanted 6" added to r. So make that 12"(pi), which is pi feet.

I'm a little slow on the uptake. (Narrow arbor :-)


Too late. The Mars lander already crashed. :-)

First Fly Rod, Reel and line Questions??
 

William Claspy wrote:
On 3/8/06 11:39 AM, in article
et, "rw"
wrote:


rb608 wrote:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

pi feet


Isn't pi the constant?

My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to d
(which we had converted from feet to inches), we have C=pi(d+6). Balances
out with 6(pi). No?

We're not adding six inches to d. We're adding one foot.

--
Cut "to the chase" for my email address.

First Fly Rod, Reel and line Questions??
 

First Fly Rod, Reel and line Questions??
 

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?


.8 feet
-tom

First Fly Rod, Reel and line Questions??
 

On 3/8/06 12:05 PM, in article
t, "rw"
wrote:

William Claspy wrote:
On 3/8/06 11:39 AM, in article
et, "rw"
wrote:


rb608 wrote:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

pi feet


Isn't pi the constant?

My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to d
(which we had converted from feet to inches), we have C=pi(d+6). Balances
out with 6(pi). No?

We're not adding six inches to d. We're adding one foot.

That's why my undergrad degree only has the WRU part of CWRU on it :-)

Bill

First Fly Rod, Reel and line Questions??
 

"Tom Nakashima" wrote in message
...

You have a rope pulled snugly around the earth at the equator (diameter
=
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?


.8 feet
-tom


Sorry, .08ft
-tom

First Fly Rod, Reel and line Questions??
 

"rb608" wrote in
news:v1EPf.40384$%I.25893@trnddc03:

"William Claspy" wrote in message
My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to
d (which we had converted from feet to inches), we have C=pi(d+6).
Balances out with 6(pi). No?

No. You're thinking correctly, but you only got halfway there.
You're actually increasing the diameter by a whole foot (6 inches each
side).

Joe F.




c1=pi*(7926 miles)*5280(feet/mile)*12(inches/ft)
c2=pi*((7926 miles)*5280(feet/mile)*12(inches/ft)+12 inches)

c2-c1=37.69 inches


--
Scott
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