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What's a boy to do?
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I don't see how it's (objectively) counter-intuitive, There are two remaining choices, switch or don't switch. I think 50:50 is an easy conclusion to draw from that. About the only thing I can figure is that it is much like many threads on ROFF in that most folks, myself included at times, don't always _read_ what they are "reading," but rather, um, infer from what is written by what they _think_ is being said. No doubt many ROFFians are guilty of that; but that is also the intentional nature of "brain teasers". In this case, they are simply ignoring that there are 3, not 2, boards and therefore, the chances cannot be 1 in 2. Not exactly, but similar IMO. There are, in fact, 2 choices remaining. The failure is that of seeing the two choices as random for the original player. Most folks, I expect, see the problem from the perspective of your "third person" for whom they *are* random. Joe F. |
What's a boy to do?
rb608 wrote: wrote in message I don't see how it's (objectively) counter-intuitive, There are two remaining choices, switch or don't switch. I think 50:50 is an easy conclusion to draw from that. Exactly......and that is precisely what makes the Monty Hall problem interesting......well, that's a part of it, anyway (more about that in just a moment). It isn't the math. Hell the math is simple enough that even I (no math wiz......by ANY stretch of the imagination) have no trouble at all in understanding and accepting various permutations of the explanation. Anyone adept at mathematics and who takes a moment to think it through will invariably come up with the right answer and, doubtless, find the whole thing rather silly. Somewhat ironically, it takes a basic knowledge of the fundamental laws of probability to figure out the wrong answer.....you have to know that tossing a coin will, in the long run, result in something very close to half heads, half tails. Anyone who doesn't know this can only guess.....and is as likely to guess right as wrong.....50:50 chance! Sweet! There is no doubt in my mind that both Craig Whitaker and Marylin vos Savant were well aware of this when the former posed the question and the latter decided to answer it. At least a couple of people have made references to the rules as I stated them in posing the problem. In fact, there were NO rules. There was simply a question about how one should proceed in a precisely and unambiguously stated situation. Suggestions and speculations about how to work through more or less similar situations (changing the "rules") may or may not be interesting in their own right, but they have nothing whatsoever to do with the original problem. I suspect that most of them have something or other to do with a certain level of discomfort engendered by the decidedly counterintuitive correct solution to the original. When all is said and done, the whole thing is a trick question. What makes it exquisitely delicious is that, as stated at the outset, I, the expositor, was not playing any kind of trick on the player......well not directly, anyway. No, what tricks the player is his or her own knowledge of probabilities and a lightning quick recognition of an absurdly easy problem. Right, Ken? O.k., that last bit was just a little unfair. Um......or was it? After all, Haddon said the pretty much same thing. Did anybody else see it? A shiny new nickel to the first to point out Haddon's own sorta nasty little trick. (hint: it's in the quotes......more or less) :) Bottom line? The Monty Hall problem really isn't much of a mathematical puzzle at all. What it IS......in spades......is a beautifully elegant probe into human psychology! As for illustrating the logic behind the correct solution, here's my own humble contribution: Let us change the scenario a bit. Instead of a single player who gets to decide whether to change his or her pick after one of the losers is exposed, let's have TWO players......Toivo and Aino. Toivo gets to pick one of the three possibilities.....Aino automatically gets the other two. All three positions are exposed. Any one may be the winner, but no one should have any difficulty in seeing that the smart money would bet on Aino. Whether in a single round or in repeated play, the odds are clearly in his favor to the tune of two to one.......67% to 33%.....not too roughly. Now, let us suppose that rather than exposing all the possibilites at once, the expositor turns over one of the boards at random. How does this change the odds? Clearly, it has absolutely no effect on the odds. O.k., so, at least one of Aino's two possibilities HAS TO be a loser.....right? After all, there are three positions and only one of them is the winner. Alright, so, if the expositor first turns over one of Aino's possibilities, which is one of the losers, how does this affect the odds? Again, it cannot possibly affect the odds......the winner and both losers are where they are.....NOTHING can affect the fact that Aino wins two times out of three.....more or less......in the long run. Now, let's go back to the problem as originally stated. Toivo is the only player. As long as he sticks with his original choice when given the option, nothing, in essence, is any different than it was in the two player game......he loses two times out of three......Aino has simply become invisible. Obvious......right? Right. O.k., so, what if Toivo chooses to jump one way one time and another the next? Beats the **** out of me (and you too, if there's an honest bone in your body). Ah, but what if Toivo changes his choice EVERY time? Well, then he quite simply BECOMES Aino!! :) Wolfgang dunkenfeld knew. |
What's a boy to do?
"Wolfgang" wrote in message oups.com... rb608 wrote: wrote in message I don't see how it's (objectively) counter-intuitive, There are two remaining choices, switch or don't switch. I think 50:50 is an easy conclusion to draw from that. Exactly......and that is precisely what makes the Monty Hall problem interesting......well, that's a part of it, anyway (more about that in just a moment). It isn't the math. Hell the math is simple enough that even I (no math wiz......by ANY stretch of the imagination) have no trouble at all in understanding and accepting various permutations of the explanation. Anyone adept at mathematics and who takes a moment to think it through will invariably come up with the right answer and, doubtless, find the whole thing rather silly. Somewhat ironically, it takes a basic knowledge of the fundamental laws of probability to figure out the wrong answer.....you have to know that tossing a coin will, in the long run, result in something very close to half heads, half tails. Anyone who doesn't know this can only guess.....and is as likely to guess right as wrong.....50:50 chance! Sweet! There is no doubt in my mind that both Craig Whitaker and Marylin vos Savant were well aware of this when the former posed the question and the latter decided to answer it. At least a couple of people have made references to the rules as I stated them in posing the problem. In fact, there were NO rules. There was simply a question about how one should proceed in a precisely and unambiguously stated situation. Suggestions and speculations about how to work through more or less similar situations (changing the "rules") may or may not be interesting in their own right, but they have nothing whatsoever to do with the original problem. I suspect that most of them have something or other to do with a certain level of discomfort engendered by the decidedly counterintuitive correct solution to the original. When all is said and done, the whole thing is a trick question. What makes it exquisitely delicious is that, as stated at the outset, I, the expositor, was not playing any kind of trick on the player......well not directly, anyway. No, what tricks the player is his or her own knowledge of probabilities and a lightning quick recognition of an absurdly easy problem. Right, Ken? O.k., that last bit was just a little unfair. Um......or was it? After all, Haddon said the pretty much same thing. Did anybody else see it? A shiny new nickel to the first to point out Haddon's own sorta nasty little trick. (hint: it's in the quotes......more or less) :) Bottom line? The Monty Hall problem really isn't much of a mathematical puzzle at all. What it IS......in spades......is a beautifully elegant probe into human psychology! As for illustrating the logic behind the correct solution, here's my own humble contribution: Let us change the scenario a bit. Instead of a single player who gets to decide whether to change his or her pick after one of the losers is exposed, let's have TWO players......Toivo and Aino. Toivo gets to pick one of the three possibilities.....Aino automatically gets the other two. All three positions are exposed. Any one may be the winner, but no one should have any difficulty in seeing that the smart money would bet on Aino. Whether in a single round or in repeated play, the odds are clearly in his favor to the tune of two to one.......67% to 33%.....not too roughly. Now, let us suppose that rather than exposing all the possibilites at once, the expositor turns over one of the boards at random. How does this change the odds? Clearly, it has absolutely no effect on the odds. O.k., so, at least one of Aino's two possibilities HAS TO be a loser.....right? After all, there are three positions and only one of them is the winner. Alright, so, if the expositor first turns over one of Aino's possibilities, which is one of the losers, how does this affect the odds? Again, it cannot possibly affect the odds......the winner and both losers are where they are.....NOTHING can affect the fact that Aino wins two times out of three.....more or less......in the long run. Now, let's go back to the problem as originally stated. Toivo is the only player. As long as he sticks with his original choice when given the option, nothing, in essence, is any different than it was in the two player game......he loses two times out of three......Aino has simply become invisible. Obvious......right? Right. O.k., so, what if Toivo chooses to jump one way one time and another the next? Beats the **** out of me (and you too, if there's an honest bone in your body). Ah, but what if Toivo changes his choice EVERY time? Well, then he quite simply BECOMES Aino!! :) Interesting illustration of how to visualize the correct strategy, but I suggest any doubters just make a spinner out of a paperclip and a piece of paper. Draw a circle, divide it into three 'pizza slices' of approximately the same area, and hold the clip in the center with a pencil tip. Decide that one 'pizza slice' is the actual prize, spin the clip to choose your intitial door, and act out the scenario. The logic behind the '2/3' answer is instantly and undeniably clear. Or, to paraphrase Wolfgang's Toivo and Aino situation, the odds of winning by switching doors after one is revealed is exactly equal to the odds that your original pick was wrong....2/3. --riverman |
What's a boy to do?
"Opus McDopus" wrote in message ... "asadi" wrote in message ... If I'm one of the remaining members I'd say your chances were pretty damned good.... john Are we goin to remain on non-speaking terms forever? Op okay, I'll give up in a couple of hours and try sending and e-mail and we'll figure out why yours are bouncing... I'd do it now but I'm busy making sure Vince wins the tontine... john |
What's a boy to do?
"asadi" wrote in message . .. okay, I'll give up in a couple of hours and try sending and e-mail and we'll figure out why yours are bouncing... I'd do it now but I'm busy making sure Vince wins the tontine... john You can get me at: or you can call me at: 828-292-9005 I'm always on speakin' terms with you, as far as you know, anyway :~^ ) Don't know why your e-mails would have bounced, but I will check my kill-file? Op |
What's a boy to do?
"Opus McDopus" wrote in message ... Don't know why your e-mails would have bounced, but I will check my kill-file? Op Nope, you aren't in Kill-file, just the usual suspects? Op |
What's a boy to do?
"Jonathan Cook" wrote in message ... riverman wrote: You toss three darts at a target. Dart A misses the target, then Dart B misses by even more. What is the probability that Dart C will miss by more than Dart A? Not enough information. But _don't_ play darts barefoot if you are prone to dropping things... Jon. Wrong on the first count, right on the second. :-) --riverman |
What's a boy to do?
Jonathan Cook wrote: riverman wrote: You toss three darts at a target. Dart A misses the target, then Dart B misses by even more. What is the probability that Dart C will miss by more than Dart A? Not enough information. That sounds right to me. However, under the circumstances I can't shake a nagging suspicion that there's a bad smell somewhere in there that I haven't noticed yet. To put it another way, while a given mathematical proposition may be clear, correct, simple and unambiguous, it does not necessarily follow that it will be easy (or even possible.....perhaps) to deal with it clearly, correctly, simply and unambiguously in plain English.....or any other natural language, for that matter. One of the beauties of the Monty Hall problem is that it illustrates this divide very nicely. Each individual who has provided a "real world" example of how to arrive at the correct solution and why it IS correct undoubtedly feels that it clear and easy to follow. The fact that several of us have taken on the task suggests otherwise. Following, as it does, closely on the heels of the MH problem, this one is naturally suspect. :) All of this points to a very fertile field of enquiry that is characterized (as well as by anything else, I think) by the fact that a lot of very bright people find anything in mathematics beyond elementary arithmetic and perhaps a bit of algebra to be a completely impenetrable mystery. Much of it IS (and has been at least since the invention of zero) counterintuitive. Anyone who doubts this would do well to consult Whitehead and Russell. But _don't_ play darts barefoot if you are prone to dropping things... Don't play darts barefoot......period. Wolfgang |
What's a boy to do?
Wolfgang wrote: Jonathan Cook wrote: riverman wrote: You toss three darts at a target. Dart A misses the target, then Dart B misses by even more. What is the probability that Dart C will miss by more than Dart A? Not enough information. That sounds right to me. However, under the circumstances I can't shake a nagging suspicion that there's a bad smell somewhere in there that I haven't noticed yet. A nice paraphrase of what I tell my students: some things are simple if you know how, and impossible if you don't. To put it another way, while a given mathematical proposition may be clear, correct, simple and unambiguous, it does not necessarily follow that it will be easy (or even possible.....perhaps) to deal with it clearly, correctly, simply and unambiguously in plain English.....or any other natural language, for that matter. One of the beauties of the Monty Hall problem is that it illustrates this divide very nicely. Each individual who has provided a "real world" example of how to arrive at the correct solution and why it IS correct undoubtedly feels that it clear and easy to follow. The fact that several of us have taken on the task suggests otherwise. One reason that math terminology exists (other than to exclude, as is with all jargon), is because many things can be explained unambiguously in math to others who speak the language, and hopefully solved in that terminology. If it were possible to put everything into non-math terms easily, we would need neither math terminology nor prerequisite knowledge. Following, as it does, closely on the heels of the MH problem, this one is naturally suspect. :) All of this points to a very fertile field of enquiry that is characterized (as well as by anything else, I think) by the fact that a lot of very bright people find anything in mathematics beyond elementary arithmetic and perhaps a bit of algebra to be a completely impenetrable mystery. Much of it IS (and has been at least since the invention of zero) counterintuitive. Anyone who doubts this would do well to consult Whitehead and Russell. No argument that math can be challenging, although I'm not sure what you mean by 'bright people'. It takes training to learn math...that old 'Royal Road' thing, but people want it to be intuitive and I suspect that this is and has always been the core of the problem. But the thing the MH puzzle does, as well as this one, is it makes people who are not well-versed in math but who feel like their intuition is the sacred measure, face their error. When faced with the contradiction between their instincts and the mathematical reality of the MH puzzle, only a fool would insist that the math is wrong and their instincts are correct. Yet many very bright people are fools. :-) But, as with many things mathematical (especially many things statistical), the key to the answer is in how you approach the solution. To answer the darts question, merely rely on the definition of probablilty: the number of ways to achieve your objective, divided by the number of possible outcomes. List all the possible arrangements of how the darts could land, and count how many fit our scenario. First, list all the ways to throw three darts, A B and C. ABC ACB BAC BCA CAB CBA Remember, we are looking at a conditional probability; dart B has already landed farther than dart A. So our list of outcomes is limited to: ABC ACB CAB Our 'definition of success' is when dart C lands further than dart A, which is clearly only the first two arrangements. So the probability of throwing a third dart that lands farther than the first (given the second dart has already landed farther than the first), is 2/3. Its an unsettling conclusion, because people want to make the argument that the distance from the bullseye affects the probability of each outcome. However, every possible distance affects every outcome equally, so they are all still equally likely, as counterintuitive as it may be. --riverman |
What's a boy to do?
riverman wrote: Wolfgang wrote: Jonathan Cook wrote: riverman wrote: You toss three darts at a target. Dart A misses the target, then Dart B misses by even more. What is the probability that Dart C will miss by more than Dart A? Not enough information. That sounds right to me. However, under the circumstances I can't shake a nagging suspicion that there's a bad smell somewhere in there that I haven't noticed yet. A nice paraphrase of what I tell my students: some things are simple if you know how, and impossible if you don't. Not to put too fine a point on it, but that would not be some things......that would be pretty much everything. To put it another way, while a given mathematical proposition may be clear, correct, simple and unambiguous, it does not necessarily follow that it will be easy (or even possible.....perhaps) to deal with it clearly, correctly, simply and unambiguously in plain English.....or any other natural language, for that matter. One of the beauties of the Monty Hall problem is that it illustrates this divide very nicely. Each individual who has provided a "real world" example of how to arrive at the correct solution and why it IS correct undoubtedly feels that it clear and easy to follow. The fact that several of us have taken on the task suggests otherwise. One reason that math terminology exists (other than to exclude, as is with all jargon), is because many things can be explained unambiguously in math to others who speak the language, and hopefully solved in that terminology. Sure. If it were possible to put everything into non-math terms easily, we would need neither math terminology nor prerequisite knowledge. True, we wouldn't need a specialized terminology. Prerequisite knowledge strikes me as a bit ambiguous......could mean any of several things. Any way I look at it, though, I can't see a way to do without it. Following, as it does, closely on the heels of the MH problem, this one is naturally suspect. :) All of this points to a very fertile field of enquiry that is characterized (as well as by anything else, I think) by the fact that a lot of very bright people find anything in mathematics beyond elementary arithmetic and perhaps a bit of algebra to be a completely impenetrable mystery. Much of it IS (and has been at least since the invention of zero) counterintuitive. Anyone who doubts this would do well to consult Whitehead and Russell. No argument that math can be challenging, although I'm not sure what you mean by 'bright people'. Well, take several PhDs vehemently defending the wrong answer to a particular simple problem, for example. As a class, PhDs are arguably reasonably bright people. More generally, I guess I mean people who show an aptitude for dealing with a variety of different kinds of problems and an ability to articulate their thoughts in a manner that is comprehensible to other concerned parties. It takes training to learn math...that old 'Royal Road' thing, but people want it to be intuitive and I suspect that this is and has always been the core of the problem. To the extent that people are more interested in solutions than problems (and I think it's fair to say that most people probably are in most instances), I suspect that they more often than not would prefer that the answers come intuitively rather than at the expense of hard mental labor. This seems to me like a perfectly reasonable position. Personally, I don't think this is "the" core of the problem that so many people have with math. I believe it's more complicated than that. For one thing, people start out as children, naturally and voraciously curious little beasts.......intellectual sponges eager to suck up whatever they can. Despite some minor variations among different tribes and cults, educational institutions and, more particularly, the cultures they serve tend to be remarkably indistinguishable in their capacity to crush that curiosity at a tender age......as they have done, for the most part, for centuries. There are many other problems. But the thing the MH puzzle does, as well as this one, is it makes people who are not well-versed in math but who feel like their intuition is the sacred measure, face their error. In theory. In practice, most just brush it aside. Ever been to Las Vegas? When faced with the contradiction between their instincts and the mathematical reality of the MH puzzle, only a fool would insist that the math is wrong and their instincts are correct. The Monty Hall problem is simple enough that trusting to intuition is easily demonstrable as a foolish course of action. That's what makes it illustrative. That's what makes it interesting. But this is by no means always the case. Take a look at competing sophisticated economic theories on the advisability of debt load sometime. Whose math are you going to believe? Intuition tells me that having more cash than debt is a good thing. Yet many very bright people are fools. :-) All bright people do foolish things, but they are NOT fools.....by definition. But, as with many things mathematical (especially many things statistical), the key to the answer is in how you approach the solution. To answer the darts question, merely rely on the definition of probablilty: the number of ways to achieve your objective, divided by the number of possible outcomes. List all the possible arrangements of how the darts could land, and count how many fit our scenario. First, list all the ways to throw three darts, A B and C. ABC ACB BAC BCA CAB CBA Remember, we are looking at a conditional probability; dart B has already landed farther than dart A. So our list of outcomes is limited to: ABC ACB CAB Our 'definition of success' is when dart C lands further than dart A, which is clearly only the first two arrangements. So the probability of throwing a third dart that lands farther than the first (given the second dart has already landed farther than the first), is 2/3. Its an unsettling conclusion, because people want to make the argument that the distance from the bullseye affects the probability of each outcome. However, every possible distance affects every outcome equally, so they are all still equally likely, as counterintuitive as it may be. I don't see anything in the above about whether the person throwing the darts is a champion player.....or drunk.....or blind. Remember, we are looking at a conditional probability; we know very little about the conditions that apply. At its root, this isn't really a math problem. Counterintuitive, nicht wahr? Wolfgang to the man with a hammer....... |
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