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First Fly Rod, Reel and line Questions??
Hello,
Thanks to everyone for your advice. I bought a Okuma Sierra reel last night for $34 which seemed to be a pretty good deal. The rod I purchased is a Quarrow Big Horn- I've never heard of the brand and couldn't find much info on them but it seems like a good deal for $45 including travel case. does anyone have any experience with this brand of rod? Now, I have to wait until payday to get line,leader,tippet,flies, etc. Then I call in sick and go fishing for a few days. From what I've heard It looks like I'll go with DT line. Now I'm looking at getting equipped for steelhead, but I think I'll build my rod eventually, and continue using good old spinning/bait casting until then. I teach at an outdoor education center and for a class project we had a custom rod builder come in for 2 hours a day for a week and 15 kids got to build their own 5ft spinning rods. A great experience for the kids and me. You guys have been very helpful-very interesting following the thread-I'm going to try and stump some of my m-athlete friends w/ the rope around the earth question. |
First Fly Rod, Reel and line Questions??
"rw" wrote in message nk.net... Wolfgang wrote: "rw" wrote in message ink.net... Wolfgang wrote: Wolfgang who, it must be admitted, has absolutely no recollection of raising a rope a foot above the earth without increasing its length being part of the original problem description. Just as you didn't recall that the rope being stretched around the equator was part of the original problem description. Actually, I did. You, on the other hand, evidently didn't recall that the problem you stated was not the original one and that therefore there was no reason for anyone to assume that the original restriction applied. In short, you made the same mistake you always do. And, yes, I'll be delighted to go into detail......if you insist. :) OK, here's the problem as Joe stated it: "You have a rope pulled snugly around the earth at the EQUATOR [emphasis mine] (diameter = 7,926 miles ±). How much length would you need to add to the rope to raise it 6 inches off the earth at all points?" Yep, that looks like it. The obvious answer, and the one that I'm sure Joe expected, and which I was the first to post, is pi feet. Thus providing a very strong hint at the same mistake you always make. There's another, less obvious answer: You don't have to add any length. Just move the rope approximately .87 miles toward either pole. Nope, the problem as stated specifically concerned the additional length needed to raise the rope. Any answer that fails to correctly state by how much the rope needs to be lengthened is not merely less obvious, it is also just plain flat wrong. Try it. See if it works. I'll try it......if you'll pay for the rope. You'll still be wrong, but it'll be fun. After all, you claim to be able to push a rope. I'd be happy to demonstrate. Hell, I'll even use the same rope. Ship it to any place in southeastern Wisconsin......I don't think I'll have much trouble finding it. :) Wolfgang |
First Fly Rod, Reel and line Questions??
Wolfgang wrote:
"rw" wrote in message nk.net... OK, here's the problem as Joe stated it: "You have a rope pulled snugly around the earth at the EQUATOR [emphasis mine] (diameter = 7,926 miles ±). How much length would you need to add to the rope to raise it 6 inches off the earth at all points?" Yep, that looks like it. The obvious answer, and the one that I'm sure Joe expected, and which I was the first to post, is pi feet. Thus providing a very strong hint at the same mistake you always make. There's another, less obvious answer: You don't have to add any length. Just move the rope approximately .87 miles toward either pole. Nope, the problem as stated specifically concerned the additional length needed to raise the rope. Any answer that fails to correctly state by how much the rope needs to be lengthened is not merely less obvious, it is also just plain flat wrong. Nope. You're recklessly "assuming" again. The problem statement doesn't state that the rope has to stay positioned over the equator -- only that it has to be "raised." There's an implicit assumption, which I think is fair, that the rope has to remain in a circular configuration. There are actually an infinite number of answers that solve the problem as stated. The problem is what mathematicians call "ill posed." On the other hand, if you take "need to add" as implying that you want to MINIMIZE the amount of extra rope, and that you aren't allowed to REMOVE rope, the unique answer (zero) is the second solution. If Joe's problem statement were to be unambiguous, with a unique answer, it should be, "You have a rope pulled snugly around the earth at the equator (diameter = 7,926 miles ±). What is the MAXIMUM length you can add to the rope to raise it 6 inches off the earth at all points?" Assuming a circular rope, of course. -- Cut "to the chase" for my email address. |
First Fly Rod, Reel and line Questions??
rw wrote in news:kYEPf.2910$Bj7.240
@newsread2.news.pas.earthlink.net: rw wrote: Scott Seidman wrote: Rats. Distributivity gets me again! There's a way to raise the rope one foot above the surface of the earth without increasing its length at all. Just move it approximately 308 miles toward either pole. Oops. I made a small arithmetic error. It should be approximately .87 miles. :-) Assuming Earth to be a perfect sphere, of course. -- Scott Reverse name to reply |
First Fly Rod, Reel and line Questions??
Scott Seidman wrote:
rw wrote in news:kYEPf.2910$Bj7.240 @newsread2.news.pas.earthlink.net: rw wrote: Scott Seidman wrote: Rats. Distributivity gets me again! There's a way to raise the rope one foot above the surface of the earth without increasing its length at all. Just move it approximately 308 miles toward either pole. Oops. I made a small arithmetic error. It should be approximately .87 miles. :-) Assuming Earth to be a perfect sphere, of course. Indeed. Also assuming a zero-diameter rope. :-) -- Cut "to the chase" for my email address. |
First Fly Rod, Reel and line Questions??
"rw" wrote in message nk.net... Nope. You're recklessly "assuming" again. We'll see. :) The problem statement doesn't state that the rope has to stay positioned over the equator Nor does it include the option of any movement other than verticle. So? -- only that it has to be "raised." Nope, not ONLY that it has to be raised. If it "has to" be raised in order to satisfy a condition in the original statement, then it "has to" be lengthened by the same logic. There's an implicit assumption, which I think is fair, that the rope has to remain in a circular configuration. There's a boatload of implicit assumptions. That's a big part of what makes the problem interesting. What is MOST interesting, on the face of it, you missed entirely despite the fact that Joe stated it explicitly. What is NOT particularly interesting is the correct answer to the problem which is, after all, simply a number of feet, centimeters, or whatever other unit of measure one wishes to use, and not an especially interesting number at that, and which is arrived at by a very simple bit of arithmetic. Also intrinsically interesting is the fact that many people fail to correctly identify the means to solve the problem and/or get the wrong answer. The smokescreen was interesting too. But, most interesting of all......well, you already given us some hints about that......and then missed the hints.....which is what really makes it interesting. There are actually an infinite number of answers that solve the problem as stated. The problem is what mathematicians call "ill posed." No, there is exactly one correct answer. The problem was very well posed. Your failure to understand it doesn't negate that. On the other hand, if you take "need to add" as implying that you want to MINIMIZE the amount of extra rope, and that you aren't allowed to REMOVE rope, the unique answer (zero) is the second solution. Well, I certainly won't argue against the proposition that it's unique. :) If Joe's problem statement were to be unambiguous, with a unique answer, it should be, "You have a rope pulled snugly around the earth at the equator (diameter = 7,926 miles ±). What is the MAXIMUM length you can add to the rope to raise it 6 inches off the earth at all points?" Well, you evidently thought it was unambiguous enough to be "the first to post" the "obvious answer" and the one that you're "sure Joe expected". I mean, how much more unambiguous can something be? Assuming a circular rope, of course. No need to assume any such thing. A flat sennit would work just as well. Wolfgang who has done a bit of fancy line work in his day. |
First Fly Rod, Reel and line Questions??
rb608 wrote:
wrote in message Assuming competent, rational reel design rather than reels "designed to sell," it's not only typical, but mathematically highly probable. For whatever reason, this reminded me of a mathematical problem whose answer is mathematically correct, but (to me anyway) seemed counterintuitive at first. Here ya go: You have a rope pulled snugly around the earth at the equator (diameter = 7,926 miles +/-). How much length would you need to add to the rope to raise it 6 inches off the earth at all points? I didn't find this problem counterintuitive, although it's a little tricky. The essential relationship is that circumference is proportional to diameter, and the constant of proportionality is pi. The only reason it might be counterintuitive is that the problem statement includes a large number (7926 miles), which is irrelevant -- a red herring. That's a tipoff in a mathematic puzzle. It doesn't matter (to the problem) what the diameter of the earth is. -- Cut "to the chase" for my email address. |
First Fly Rod, Reel and line Questions??
Wolfgang wrote:
rw wrote: "You have a rope pulled snugly around the earth at the EQUATOR [emphasis mine] (diameter = 7,926 miles ±). How much length would you need to add to the rope to raise it 6 inches off the earth at all points?" The problem statement doesn't state that the rope has to stay positioned over the equator Nor does it include the option of any movement other than verticle. So? Good god, would you please learn how to read! The question was ambiguous in that respect. It doesn't state that you can or can not move the rope away from the equator. Correct answers range from -7926miles*pi to +1ft*pi. I like to argue with RW as much as the next guy, but his answer of 0 was pretty nice. - Ken |
First Fly Rod, Reel and line Questions??
"rw" wrote in message nk.net... rb608 wrote: wrote in message Assuming competent, rational reel design rather than reels "designed to sell," it's not only typical, but mathematically highly probable. For whatever reason, this reminded me of a mathematical problem whose answer is mathematically correct, but (to me anyway) seemed counterintuitive at first. Here ya go: You have a rope pulled snugly around the earth at the equator (diameter = 7,926 miles +/-). How much length would you need to add to the rope to raise it 6 inches off the earth at all points? I didn't find this problem counterintuitive, Presumably because you have no idea of what the word means. although it's a little tricky. Tricky? Good lord. There is nothing the least bit tricky about it. It's a simple problem in arithmetic. Even you (whose skills are such that you can pose a similar problem.....and then provide an answer that's off by more than three orders of magnitude) got it right. The essential relationship is that circumference is proportional to diameter, and the constant of proportionality is pi. No kidding? Is that the tricky part? The only reason it might be counterintuitive is that the problem statement includes a large number (7926 miles), which is irrelevant -- a red herring. Not a red herring. It's a fact (or a close enough approximation, anyway) and it is ESSENTIAL to what makes the answer IN FACT counterintuitive. That's a tipoff in a mathematic puzzle. We'll try to keep that in mind should we encounter a mathematical puzzle. Meanwhile, it might (it probably won't......but it might) interest you to know thats it's also a tipoff to what makes the answer to this little arithmetical exercise COUNTERINTUITIVE! It doesn't matter (to the problem) what the diameter of the earth is. Well, lookee here......the thread is not yet a day old and you've already found a clue! What a lucky boy you are! :) Wolfgang |
First Fly Rod, Reel and line Questions??
wrote in message ... Wolfgang wrote: rw wrote: "You have a rope pulled snugly around the earth at the EQUATOR [emphasis mine] (diameter = 7,926 miles ±). How much length would you need to add to the rope to raise it 6 inches off the earth at all points?" The problem statement doesn't state that the rope has to stay positioned over the equator Nor does it include the option of any movement other than verticle. So? Good god, would you please learn how to read! Hee, hee, hee. The question was ambiguous in that respect. It doesn't state that you can or can not move the rope away from the equator. There was nothing at all ambiguous about it. The problem as stated said nothing at all about movement other than vertical. It DID ask by how much the rope would need to be LENGTHENED to RAISE it 6 inches. If you are still having trouble with what it means to raise something, try to think of what happens to you relative to the position of your seat (or to your blood pressure, for that matter) every time I do this to you. That should help. :) Correct answers range from -7926miles*pi to +1ft*pi. Nope. Only one right answer I like to argue with RW as much as the next guy, Everybody should have a hobby he can hope to master someday. but his answer of 0 was pretty nice. No, it was just stupid. Wolfgang who assumes he is not the only one to notice that slow learners tend to come out to play in groups. :) |
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