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What's a boy to do?
"riverman" wrote in news:1162253876.219819.310220
@m7g2000cwm.googlegroups.com: Remember, we are looking at a conditional probability; dart B has already landed farther than dart A. So our list of outcomes is limited to: ABC ACB CAB Reducing this to a combinatorial problem is incorrect and misleading. Each dart has a distribution around some point, hopefully the center, with decreasing probability as you get further from the target. If darts A and B are three or four standard deviations out, dart C has a very high probability of being closer to the center. If A and B are a tenth of a standard deviation out, there is a very low probability of C being closer. We need to know the 2-D distribution of the dart C, and then we need to know where the first two darts landed. So "not enough information" is correct. -- Scott Reverse name to reply |
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Calif Bill wrote: You could have an almost infinite amount of darts the exact same distance from the center. The only limiting number is how big the circle is from the center and how big of diameter is the dart. There are an infinite number of points equidistant from the center point. And it depends on neither the precision or accuracy of the measurement. And in your measurement of the distance it would be more accuracy and not precision. Precision only gives more numbers after the decimal point. Bill: I'm not sure where to start, but there are a lot of little details in your assertations that are erroneous. There's some truth also, so don't lose hope :-) First of all, yes the definition of a circle states there are an infinite number of points in a plane that are equidistant from a given point, but the liklihood of getting even two darts to land on that circle is slim. (Just how slim is discussed in the second paragraph below.) We don't even have to agree on how slim for now, but the the more darts you want to have land on that circle, the less likely it is to happen, and it approaches zero as the number of darts gets larger and larger. Although the phrase 'almost infinite' is actually meaningless, I assume you mean we are looking at numbers that are growing huge beyond comprehension, so the liklihood of it happening is shrinking tiny beyond comprehension. Secondly, it IS a matter of precision, not accuracy. We don't care what the actual distance from the center is, what we do care about is whether or not two darts have the same measurement from the center, even if that measurement is wrong. If we use an inaccurate tool, then we might get a wrong amount (a broken ruler might show each dart to be 10.55 cm from the center, while they are both actually much less that that). That's 'inaccurate', but if the numbers match, then we can still assert that they are the same distance. If we use a ruler with really fat indicator lines, we might get both measuring 10.55 cm, however if we used a vernier caliper, calibrated or not, we might get one of them measuring 10.550000000000001 cm and the other measuring 10.550000000000002 cm. Those are measures of high PRECISION, and my assertation is that, no matter how the darts land, we can always use more precise measuring devices until we find where the numbers vary. And they always will, even if we have to go to electron microscope levels. Just as no two snowflakes are alike, no two darts can land the same distance from the center. Now, I appreciate that some people might have an ingrained prejudice against math because it doesn't always conform to their intuition (and this might be you, or it might not). But when faced with something that doesn't seem to 'fit' what we want to believe, there are two choices: find out the rules of math and learn to analyze things according to those rules, including learning the constraints and limitations and the meaning of those, or else continue to assert that what we believe is right because it 'feels right' to us, and use poorly structured arguments or misnomers to claim that nothing has any validity, so we can't possibly be wrong. That way lies madness. --riverman |
What's a boy to do?
Scott Seidman wrote: ...Each dart has a distribution around some point, hopefully the center, with decreasing probability as you get further from the target. I detect a troublesome ambiguity here. I see two ways to read this without the reader doing any violence to good sense: 1. Each dart has a distribution around some point, hopefully the center, with decreasing probability of being close to the center as the thrower gets further from the target. 2. Each dart has a distribution around some point, hopefully the center, with decreasing probability of landing at any point as distance from the center increases. I think no one will have much trouble with the first reading. The second is easier to defend than it may appear at a glance because it is.....partly.....true. I assume that a truly great dart thower can consistently place the darts very close to the center of the board (which, as we all know is not necessarily the object in every game, but is as good a spot as any other and does, at any rate, appear to be accepted for the purposes of this discussion) and I know that there are people whose skills are so abysmal that they rarely hit the board at all from the standard distance of what I believe to be 8 feet or so. Probabilities of distribution clearly vary widely (if not to say wildly) between these two extremes. What makes the second reading defensible is that for the best dart throwers the probability of landing at a given point DOES decrease with distance from the center.....um.....mostly. In fact, it also decreases as the point gets very very close to a precisely measured center. The same is also true for ALL dart throwers. The difference among them is that the diameter of the circle at which increasing or decreasing probabilities converge or diverge (depending on direction of travel toward or away from the circle) varies with the skill of the thrower, being very small for the very good and very large for the very bad. I haven't looked at this, or the larger discussion, closely enough to suppose that it will be a crushing blow to anyone's thesis but, on the other hand, I haven't seen anything yet that I think rules it out either. It may not even be relevant or interesting given the assumptions that have been (if only tacitly) agreed on. However, it does once again open the door to an examination of those assumptions. Given that no one showed any interest the first time I brought the matter up though, I guess I won't go into it in any depth here. I will simply confine myself to making a proposition open to anyone. Give me three darts and a prediction of where they will land relative to one another in terms of distance from the center of the target, and I will prove you wrong EVERY time. :) Wolfgang |
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Jonathan Cook wrote: riverman wrote: solution. To answer the darts question, merely rely on the definition of probablilty: the number of ways to achieve your objective, divided by the number of possible outcomes. List all the possible arrangements of how the darts could land, and count how many fit our scenario. I saw your response to my post, but I still disagree. You are making all sorts of assumptions by reducing it to this simple model, not the least of which is some sort of uniform probability distribution, or worse yet, a 50-50 likelihood of landing inside or outside of dart A. And those assumptions _heavily_ depend on how closely dart A is to the target, among other things (like if I'm throwing, who has very little dart-throwing experience). Dart throwing is _nothing_ like dice rolling... First, list all the ways to throw three darts, A B and C. ABC ACB BAC BCA CAB CBA Sometime too simple _is_ too simple... But, Wolfgang's original post has got me thinking, and I'd be interested to see your response to a post I'm about to make from his original question (and Wolfgang's and any others' responses, too.) Jon. Hi Jon: Actually, I'm not assuming a uniform distribution, just an unchanging one. I think the only crucial assumption here (beyond the obvious ones: gravity is constant, the target is planar, the darts are self-similar, the wind doesn't change, etc) is that the skill of the thrower does not improve or deteriorate demonstrably between throws, and that the thrower is aiming for the same spot with each throw. Some people are NOT assuming these things, and I agree that it skews the results, and I'll acquiesce and say that I should have stated those things and not assumed them. The nonsense about two darts being able to be equidistant is just that: nonsense. But if we assume the conditions are identical for all three darts, then each throw is identical without prejudice, and the six outcomes are equally likely, and the answer is 2/3. Take this problem across the hall to the Stats professors and see what they have to say about it. Your other assertations about probabilities not being meaningful in the context of singular events sounds bizarre. I'll re-read what you wrote, mostly because I see you have some education in math and statistics, but it sounds like you are getting twisted around somewhere. Possibly within the definition of 'probability'. --riverman |
What's a boy to do?
riverman wrote: ....If we use a ruler with really fat indicator lines, we might get both measuring 10.55 cm, however if we used a vernier caliper, calibrated or not, we might get one of them measuring 10.550000000000001 cm and the other measuring 10.550000000000002 cm. Those are measures of high PRECISION, and my assertation is that, no matter how the darts land, we can always use more precise measuring devices until we find where the numbers vary.... If you can REALLY measure things on a scale several orders of magnitude short of an angstrom, I REALLY wanna come play in your shop! :) For the benefit of those who don't know what a vernier caliper is (a friend of mine....who should have known better.....once thought a micrometer I handed him was some sort of special application c-clamp and proceeded to see how tight he could crank it.....I nearly smacked his ****in' hea......well, never mind about that), suffice it to say that the numbers displayed above were used for effect but Myron's point is indisputable. Precision measuring instruments these days are such that finding two darts whose distance from a given point is so close that the difference can't be measured is vanishingly small. The REAL difficulty (whether in a pub or a laboratory) would be in getting agreement on exactly where to measure from. Wolfgang |
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"riverman" wrote in message oups.com... Calif Bill wrote: You could have an almost infinite amount of darts the exact same distance from the center. The only limiting number is how big the circle is from the center and how big of diameter is the dart. There are an infinite number of points equidistant from the center point. And it depends on neither the precision or accuracy of the measurement. And in your measurement of the distance it would be more accuracy and not precision. Precision only gives more numbers after the decimal point. Bill: I'm not sure where to start, but there are a lot of little details in your assertations that are erroneous. There's some truth also, so don't lose hope :-) First of all, yes the definition of a circle states there are an infinite number of points in a plane that are equidistant from a given point, but the liklihood of getting even two darts to land on that circle is slim. (Just how slim is discussed in the second paragraph below.) We don't even have to agree on how slim for now, but the the more darts you want to have land on that circle, the less likely it is to happen, and it approaches zero as the number of darts gets larger and larger. Although the phrase 'almost infinite' is actually meaningless, I assume you mean we are looking at numbers that are growing huge beyond comprehension, so the liklihood of it happening is shrinking tiny beyond comprehension. Secondly, it IS a matter of precision, not accuracy. We don't care what the actual distance from the center is, what we do care about is whether or not two darts have the same measurement from the center, even if that measurement is wrong. If we use an inaccurate tool, then we might get a wrong amount (a broken ruler might show each dart to be 10.55 cm from the center, while they are both actually much less that that). That's 'inaccurate', but if the numbers match, then we can still assert that they are the same distance. If we use a ruler with really fat indicator lines, we might get both measuring 10.55 cm, however if we used a vernier caliper, calibrated or not, we might get one of them measuring 10.550000000000001 cm and the other measuring 10.550000000000002 cm. Those are measures of high PRECISION, and my assertation is that, no matter how the darts land, we can always use more precise measuring devices until we find where the numbers vary. And they always will, even if we have to go to electron microscope levels. Just as no two snowflakes are alike, no two darts can land the same distance from the center. Now, I appreciate that some people might have an ingrained prejudice against math because it doesn't always conform to their intuition (and this might be you, or it might not). But when faced with something that doesn't seem to 'fit' what we want to believe, there are two choices: find out the rules of math and learn to analyze things according to those rules, including learning the constraints and limitations and the meaning of those, or else continue to assert that what we believe is right because it 'feels right' to us, and use poorly structured arguments or misnomers to claim that nothing has any validity, so we can't possibly be wrong. That way lies madness. --riverman Your statement was no two darts could land equidistant from the center. As I state, totally wrong. There is an infinite number of points on the circle where the first dart landed from the center. You change the statement to say the more darts that are thrown, the likelihood that two are equidistant from the center diminishes. The more darts tossed the greater the likelihood two are equidistant. Not all equidistant, but two can be. Sure, your vernier calipers can have more precision than a wooden school rule, but it is still the accuracy of the measurement. Your statement is akin to saying you have increased precision when you multiply 1.02 times 2.04 and get 2.0808. You still have only 2 decimal points of precision. As to using an accurate tool, does not need to be. The actual measurement may be wrong, but as long as the measurement is the same is all we need to know for the stated question. As long as the precision and accuracy is great enough in the measuring instrument to have repeatability, the actual distance matters not. Maybe you should go back and review the rules of math. And review your arguments. |
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Scott Seidman wrote: "riverman" wrote in news:1162253876.219819.310220 @m7g2000cwm.googlegroups.com: Remember, we are looking at a conditional probability; dart B has already landed farther than dart A. So our list of outcomes is limited to: ABC ACB CAB Reducing this to a combinatorial problem is incorrect and misleading. Each dart has a distribution around some point, hopefully the center, with decreasing probability as you get further from the target. If darts A and B are three or four standard deviations out, dart C has a very high probability of being closer to the center. If A and B are a tenth of a standard deviation out, there is a very low probability of C being closer. We need to know the 2-D distribution of the dart C, and then we need to know where the first two darts landed. So "not enough information" is correct. But consider that outcome of throwing each dart is independant. IOW, there will always be one dart that is closest, one that is farthest, one that is in between. The combinatoric arrangement merely gives all the arrangements. Yes, if Dart A is very very close, then the probability of dart B being closer gets smaller. But that same distribution gets repeated again with dart B being closer than A if we throw dart B first. So, unless the ability of the thrower changes between the two darts, AB is identical to BA. --riverman |
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What's a boy to do?
"Kevin Vang" wrote in message t... In article t, says... Your statement was no two darts could land equidistant from the center. As I state, totally wrong. Two darts could conceivable land equidistant from the center; however, the probability of that happening is 0. Explaining why will require a bit of less than elementary probability theory, with integral calculus as a prerequisite. We can go there, if you are up to it... Kevin Explain why could not happen. |
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Calif Bill wrote: "Kevin Vang" wrote in message t... In article t, says... Your statement was no two darts could land equidistant from the center. As I state, totally wrong. Two darts could conceivable land equidistant from the center; however, the probability of that happening is 0. Explaining why will require a bit of less than elementary probability theory, with integral calculus as a prerequisite. We can go there, if you are up to it... Kevin Explain why could not happen. I don't know if you have taken Integral Calculus, so I won't use that to explain it. The simplest 'geometrically appealing' explanation is to say that the probability of hitting some target is directly related to the size of the target. The bigger the spot you are trying to hit, the more likely it is to hit it. Now, if you are aiming for a curved line....specifically the line that describes a circle, you have to consider the width of that line. Since circles are a collection of points, and points have no width, then you are essentially aiming for something that has a width of zero. Which means the possibility of hitting it is zero. You can hit it ONCE, because its position is unknown until the first dart actually lands. Once that dart establishes the position of the circle, it becomes a target of width zero which another dart cannot possibly hit. You can reduce the size of your miss (lets call it your 'slop') to be as small as you want by making less and less precise measurements, but the converse is also true...you can always find the slop by increasing the precision of your measurement. You cannot eliminate the slop; you cannot ever hit the line.: its a matter of precision. Just like no two snowflakes are alike. Throwing more and more darts DOES increase the liklihood of hitting something more than once, but if the liklihood of hitting it is already infinitely small; throwing more and more darts doesn't make it any more likely. Throwing infinite darts creates what is called an 'indeterminate' form, and we cannot solve it that way. We get an infinitely large number of opportunities of achieving something that has an infinitely small chance of happening. Its incorrect to conclude that it will happen infinite times....Infinity x (1/infinity) does not equal infinity. It doesn't equal, or mean, anything. However, throwing a FINITE number of darts....say two, at something that we have an infintely small chance of hitting IS solvable. Its three times 'infinitely small', which is still 'infinitely small'. If you have taken any calculus, you know the value of 'infintely small' is zero. --riverman |
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