Future Fanatic;96347 Wrote:
I found this:

"As to flies tied on larger hooks(4-5/0), the number of turns needed to
provide the optimal torque, 3.24 x 10 to the fourth power negative
centripetal force accelerated toward the shank of the hook, is based in
McClingon’s constant. That constant dictates that one turn is needed
for a size “5” thread (based on the Buford Scale) for each 153 microns
of hook shank(or rotational axis) diameter. For example, a hook shank
that is 500 microns in diameter, would need a minimum of four wraps.
Of course, the material that is to be tied to the shank of the hook
increases the diameter of the wrap and therefore increasing the
centripetal force needed to secure it to the shank of the hook. Thus
the diameter of the material that is to be tied to the hook is to be
calculated using a factor of .5 of McClingon’s constant. It must be
added that if one increases the size of the thread usedby one Buford
unit, the number of wraps decreases by a factor of .347( and increases
at that same rate when one decreases the size of the thread by one
Buford unit)"

You know,

I never thought of it that way.....but it DOES make a lot of sense!

My lofty take....
Maybe because an odd number has a more organic look or feel to it. Use
four or six wraps when building a robot, but five wraps on a Spey!
~James


--
jcstikfish

'www.autumnbrookangling.com' (http://tinyurl.com/3869da)
Custom Flies and NJ Guide Service

'ABA Fly Fishing Journal' (http://tinyurl.com/34lzt6)
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