Future Fanatic wrote:
I found this:

"As to flies tied on larger hooks(4-5/0), the number of turns needed to
provide the optimal torque, 3.24 x 10 to the fourth power negative
centripetal force accelerated toward the shank of the hook, is based in
McClingon’s constant. That constant dictates that one turn is needed
for a size “5” thread (based on the Buford Scale) for each 153 microns
of hook shank(or rotational axis) diameter. For example, a hook shank
that is 500 microns in diameter, would need a minimum of four wraps.
Of course, the material that is to be tied to the shank of the hook
increases the diameter of the wrap and therefore increasing the
centripetal force needed to secure it to the shank of the hook. Thus
the diameter of the material that is to be tied to the hook is to be
calculated using a factor of .5 of McClingon’s constant. It must be
added that if one increases the size of the thread usedby one Buford
unit, the number of wraps decreases by a factor of .347( and increases
at that same rate when one decreases the size of the thread by one
Buford unit)"




Please keep your units standard. Hook shanks are referred to by gauge
(American Wire Gauge, AWG), not by diameter.

Diameters can be calculated by applying the formula:

D(AWG)=.005·92^((36-AWG)/39) inch.

For the 00, 000, 0000 etc. gauges you use -1, -2, -3, which makes more
sense mathematically than "double nought." This means that in American
wire gage every 6 gauge decrease gives a doubling of the wire diameter,
and every 3 gauge decrease doubles the wire cross sectional area.
Similar to dB in signal and power levels.

Conversion to microns is left to the reader.

--
Cut "to the chase" for my email address.