First Fly Rod, Reel and line Questions??

On 8 Mar 2006 17:05:57 GMT, Scott Seidman
wrote:

This feeling was reinforced when I started seeing mid arbor reels.

Brilliant! And, as a NCer would say, hilarious.

d;o)

You have a rope pulled snugly around the earth at the equator (diameter
=
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?


..08 ft.
or approx, 1" .960" to be exact.
-tom

On Wed, 08 Mar 2006 16:26:46 GMT, "rb608"
wrote:

wrote in message
Assuming competent, rational reel design rather than reels "designed to
sell," it's not only typical, but mathematically highly probable.

For whatever reason, this reminded me of a mathematical problem whose answer
is mathematically correct, but (to me anyway) seemed counterintuitive at
first. Here ya go:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

Joe F

OK. You have a piece of fly line wrapped around a pencil (diameter =
approx. 1/4"). How much length would you need to add to it to raise it
6 inches off the pencil at all points? You have a chain wrapped around
the rear wheel and tire of a tractor (diameter = 5 feet). How much
length would you need to add to the chain to raise it 6 inches off the
tire at all points?

This might provide insight as to why the rope around the equator of the
earth seems counterintuitive. Think about the result you want versus to
what you're comparing it - using the figure of 7,926 miles is what makes
it counterintuitive, because it's the wrong thing to compare with
desired result - the 6 inch (radius)/12 inch (diameter) increase.

HTH,
R

rw wrote in news:QmEPf.1822$x94.1172
@newsread1.news.pas.earthlink.net:

Scott Seidman wrote:
"rb608" wrote in
news:v1EPf.40384$%I.25893@trnddc03:


"William Claspy" wrote in message

My guess was 6(pi) inches. It's C=pi(d), so if we add six inches to
d (which we had converted from feet to inches), we have C=pi(d+6).
Balances out with 6(pi). No?

No. You're thinking correctly, but you only got halfway there.
You're actually increasing the diameter by a whole foot (6 inches each
side).

Joe F.





c1=pi*(7926 miles)*5280(feet/mile)*12(inches/ft)
c2=pi*((7926 miles)*5280(feet/mile)*12(inches/ft)+12 inches)

c2-c1=37.69 inches

Correct, but much more complicated than necessary.

c1 = pi*d
c2 = pi*(d+(1 foot))
c2-c1 = pi feet


Rats. Distributivity gets me again!

--
Scott
Reverse name to reply

On Wed, 08 Mar 2006 16:39:47 GMT, rw
wrote:

rb608 wrote:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

pi feet

hairy palms

Scott Seidman wrote:

Rats. Distributivity gets me again!

There's a way to raise the rope one foot above the surface of the earth
without increasing its length at all. Just move it approximately 308
miles toward either pole.

Unfortunately, you'll run up against one of the primary tenets of
engineering: You can't push a rope. :-)

--
Cut "to the chase" for my email address.

"rw" wrote in message
k.net...
Scott Seidman wrote:

Rats. Distributivity gets me again!

There's a way to raise the rope one foot above the surface of the earth
without increasing its length at all. Just move it approximately 308 miles
toward either pole.

Assuming your rope initially follows any circumference other than the
equator this is impossible.

Unfortunately, you'll run up against one of the primary tenets of
engineering: You can't push a rope. :-)

Which demonstrates one of the primary failings of engineering AND the value
of semantics quite nicely. In fact, you most certainly CAN push a rope.


Wolfgang

In article aBDPf.28667$W42.17593@trnddc02, junkmail608
@verizNOSPAMon.net says...
wrote in message
Assuming competent, rational reel design rather than reels "designed to
sell," it's not only typical, but mathematically highly probable.

For whatever reason, this reminded me of a mathematical problem whose answer
is mathematically correct, but (to me anyway) seemed counterintuitive at
first. Here ya go:

You have a rope pulled snugly around the earth at the equator (diameter =
7,926 miles +/-). How much length would you need to add to the rope to
raise it 6 inches off the earth at all points?

Joe F.

pi*12" or ~38"?
- Ken

rw wrote:
Scott Seidman wrote:


Rats. Distributivity gets me again!


There's a way to raise the rope one foot above the surface of the earth
without increasing its length at all. Just move it approximately 308
miles toward either pole.

Oops. I made a small arithmetic error. It should be approximately .87
miles. :-)

--
Cut "to the chase" for my email address.

Wolfgang wrote:
"rw" wrote in message
k.net...

Scott Seidman wrote:

Rats. Distributivity gets me again!

There's a way to raise the rope one foot above the surface of the earth
without increasing its length at all. Just move it approximately 308 miles
toward either pole.


Assuming your rope initially follows any circumference other than the
equator this is impossible.

That was part of the problem description: "You have a rope pulled snugly
around the earth at the equator."

--
Cut "to the chase" for my email address.