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#31
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#32
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On Nov 10, 6:04*pm, rb608 wrote:
On Nov 10, 6:22*am, wrote: Some considerations on casting and rod loading. A simple calculation for casting in air is; Frt = Fi * Fa * Ff * Flt Where Frt = the force on the rod tip in kg.m/s², Fi = inertia (mass) in grams, Ff = the coefficient of fluid kinetic friction µk ( air resistance), Fa = the acceleration of the line in ms², and Flt = line tension in kg.m/s² Now, I admittedly can't haul worth a ****, but I do know my physics (maybe that's my problem.) *I'm having a bit of difficulty reconciling your theory above with that of Mr. Newton who opined a much simpler equation, F=ma. Force equals mass times acceleration. *That's it. The extra terms you included (Ff and Flt) are misplaced IMO. *Under no circumstances would they be multiplication terms in the equation. *The line tension is just another Force that would be part of the net force on the tip of the rod, not a separate term. The air resistance term (what units are you thinking for that one?) also does not belong there. *Any resisting forces due to fluid friction would similarly be a part of the net value of the Force at the rod tip. *It does not belong in the equation as a multiplicative term. As I said, I can't haul; but I fear the inaccuracies of your mathematical equation may be detracting from your practical instruction. The coefficient of fluid friction, usually indicated by " µk " is a dimensionless scalar value. The rest of what you have written makes no sense in regard to the equations and explanations I gave. The units used for tension = Newtons. The units used for force on the rod tip = Newtons. The rest is self explanatory. As indeed is the theory itself after a little thought. I am not here to give people basic algebra, nor to explain mathematical concepts. The theory itself has already proven extremely valuable in teaching people to cast. If you don´t understand it, then that is your problem not mine. Do you understand E=mc² or is it too simplistic for you? |
#33
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rb608 wrote:
On Nov 10, 6:22 am, wrote: Some considerations on casting and rod loading. A simple calculation for casting in air is; Frt = Fi * Fa * Ff * Flt Where Frt = the force on the rod tip in kg.m/s², Fi = inertia (mass) in grams, Ff = the coefficient of fluid kinetic friction µk ( air resistance), Fa = the acceleration of the line in ms², and Flt = line tension in kg.m/s² Now, I admittedly can't haul worth a ****, but I do know my physics (maybe that's my problem.) I'm having a bit of difficulty reconciling your theory above with that of Mr. Newton who opined a much simpler equation, F=ma. Hey, he's using Newtons! Can't you read, dumbo? -- Cut "to the chase" for my email address. |
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#36
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On Nov 10, 6:19*pm, Tim Lysyk wrote:
wrote: On Nov 10, 5:50 pm, Scott Seidman wrote: wrote in news:af6faa37-7c18-480a-ba93- : Probably a good idea, teachers should have open minds, and actually look at theories and equations before they simply trash them out of hand. You still have not said a single sensible word about the theory, or the equations. *The only possible conclusions are, that you either don ït want to do so because you are stupid and biased, or you are just too stupid to so so at all. I feel sorry for your students. I haven't looked through your equations, because I don't know why I should. *If a student handed me a manifesto like that, I'd hand it back and ask him or her to do a better job. Step one would be to tell your reader WHY you are doing this exercise. * What do you expect to show us? *A model that you are asking a question is a valuable tool, but a model in a vacuum is masturbation. I gave up even trying to figure this out when I saw acceleration in units of "ms^2" instead of ms^(-2) -- Scott Reverse name to reply That is the standard European unit notation for Newtons. That should be quite obvious, and as you correctly translated the unit you mentioned to the standard American notation ms^(-2), *( which is also merely a variation of standard mathematical notation, you can´t be completely stupid. http://de.wikipedia.org/wiki/Newton_(Einheit) ( Doubtless you can find it in English as well). It makes no difference to me whether you look at it or not, or whether you try to trash it without looking at it, doing so merely demonstrates your stupidity, inertia, and bias. Those are not very good traits for somebody who purportedly teaches graduate engineering. The reason for the exercise is to discover the optimum casting stroke and demonstrate it mathematically for any given parameters. There are other reasons as well, testing various combinations of rod and line, and building a graphic simulation of the process. This is already in hand. Nobody is forcing you to look at or believe anything at all. If you merely wish to demonstrate how stupid you are, by trashing something without either looking at it, or understanding it, that is just fine with me. You STILL have not written a single sensible word in regard to either the theory, or the equations. Just more silly bull****. I think Scott was refering your phrase: "Fa = the acceleration of the line in ms²". *Acceleration is usually expressed as change in disrance per some unit of time, such as m/(s^2), or meters divided by seconds squared. You have it as meters times seconds squared. Tim Lysyk That is not the case, you obviously use different notation. The notation I use is the standard SI notation, as shown here; http://img73.imageshack.us/my.php?image=nonameyt7.jpg If you wish to use your notation, then go ahead, it is simple to convert to whatever notation you please, merely substitute the units you do not agree with. Makes no difference at all to the equations. |
#37
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rw wrote:
wrote: Do you understand E=mc² or is it too simplistic for you? Of course! Now I get it! You're casting with relativistic velocity and converting the energy of the haul into mass, resulting in much better shooting. Brilliant! Casting at the speed of light. What an elegantly simple solution to the double haul. I'm gonna need to hit the gym. ;-) -- Ken Fortenberry |
#38
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wrote:
On Nov 10, 6:19 pm, Tim Lysyk wrote: wrote: On Nov 10, 5:50 pm, Scott Seidman wrote: wrote in news:af6faa37-7c18-480a-ba93- : Probably a good idea, teachers should have open minds, and actually look at theories and equations before they simply trash them out of hand. You still have not said a single sensible word about the theory, or the equations. The only possible conclusions are, that you either don ït want to do so because you are stupid and biased, or you are just too stupid to so so at all. I feel sorry for your students. I haven't looked through your equations, because I don't know why I should. If a student handed me a manifesto like that, I'd hand it back and ask him or her to do a better job. Step one would be to tell your reader WHY you are doing this exercise. What do you expect to show us? A model that you are asking a question is a valuable tool, but a model in a vacuum is masturbation. I gave up even trying to figure this out when I saw acceleration in units of "ms^2" instead of ms^(-2) -- Scott Reverse name to reply That is the standard European unit notation for Newtons. That should be quite obvious, and as you correctly translated the unit you mentioned to the standard American notation ms^(-2), ( which is also merely a variation of standard mathematical notation, you can´t be completely stupid. http://de.wikipedia.org/wiki/Newton_(Einheit) ( Doubtless you can find it in English as well). It makes no difference to me whether you look at it or not, or whether you try to trash it without looking at it, doing so merely demonstrates your stupidity, inertia, and bias. Those are not very good traits for somebody who purportedly teaches graduate engineering. The reason for the exercise is to discover the optimum casting stroke and demonstrate it mathematically for any given parameters. There are other reasons as well, testing various combinations of rod and line, and building a graphic simulation of the process. This is already in hand. Nobody is forcing you to look at or believe anything at all. If you merely wish to demonstrate how stupid you are, by trashing something without either looking at it, or understanding it, that is just fine with me. You STILL have not written a single sensible word in regard to either the theory, or the equations. Just more silly bull****. I think Scott was refering your phrase: "Fa = the acceleration of the line in ms²". Acceleration is usually expressed as change in disrance per some unit of time, such as m/(s^2), or meters divided by seconds squared. You have it as meters times seconds squared. Tim Lysyk That is not the case, you obviously use different notation. The notation I use is the standard SI notation, as shown here; http://img73.imageshack.us/my.php?image=nonameyt7.jpg Uh, unless I'm hallucinating, that web site contradicts your "notation." -- Cut "to the chase" for my email address. |
#39
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#40
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On Nov 10, 12:18*pm, wrote:
The coefficient of fluid friction, usually indicated by " µk " is a dimensionless scalar value. That being the case, the units will not match on both sides of the equation, at least not as you've described the variables. And if it's dimensionless, how do you account for its variability with velocity? Is it friction drag or pressure drag? The units used for tension = Newtons. *The units used for force on the rod tip = Newtons. *The rest is self explanatory. As indeed is the theory itself after a little thought. What should be self explanatory is that the rod tip Newtons on the left are cancelled by the tension term Newtons on the right, leaving the left side unitless with kg.m^(-2) on the right. That doesn't work. I am not here to give people basic algebra, nor to explain mathematical concepts. Okay. The theory itself has already proven extremely valuable in *teaching people to cast. I have not discussed your theory, only with your mathematical modeling of it. Anybody who could teach me to double haul would have my respect; but not by insulting my intelligence., Do you understand E=mc² * or is it too simplistic for you? No, I'm down wit dat. As my #20 Griffith's Gnat approaches c, it approaches the size of a #6 and the time it takes to reach the trout slows down, giving me more time for an upstream mend; but it doesn't matter because my 3 wt rod now weighs 12,000,000 Newtons. |
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