Hauling, Rod-loading.

On Nov 10, 6:04*pm, rb608 wrote:
On Nov 10, 6:22*am, wrote:

Some considerations on casting and rod loading.

A simple calculation for casting in air is;

Frt = Fi * Fa * Ff * Flt

Where Frt = the force on the rod tip in kg.m/s², Fi = inertia (mass)
in grams, Ff = the coefficient of fluid kinetic friction µk ( air
resistance), Fa = the acceleration of the line in ms², and Flt = line
tension in kg.m/s²

Now, I admittedly can't haul worth a ****, but I do know my physics
(maybe that's my problem.) *I'm having a bit of difficulty reconciling
your theory above with that of Mr. Newton who opined a much simpler
equation, F=ma.

Force equals mass times acceleration. *That's it.

The extra terms you included (Ff and Flt) are misplaced IMO. *Under no
circumstances would they be multiplication terms in the equation. *The
line tension is just another Force that would be part of the net force
on the tip of the rod, not a separate term.

The air resistance term (what units are you thinking for that one?)
also does not belong there. *Any resisting forces due to fluid
friction would similarly be a part of the net value of the Force at
the rod tip. *It does not belong in the equation as a multiplicative
term.

As I said, I can't haul; but I fear the inaccuracies of your
mathematical equation may be detracting from your practical
instruction.

The coefficient of fluid friction, usually indicated by " µk " is a
dimensionless scalar value.

The rest of what you have written makes no sense in regard to the
equations and explanations I gave.

The units used for tension = Newtons. The units used for force on the
rod tip = Newtons. The rest is self explanatory. As indeed is the
theory itself after a little thought.

I am not here to give people basic algebra, nor to explain
mathematical concepts.

The theory itself has already proven extremely valuable in teaching
people to cast.

If you don´t understand it, then that is your problem not mine.

Do you understand E=mc² or is it too simplistic for you?