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  #1  
Old October 17th, 2007, 07:58 PM posted to rec.outdoors.fishing.fly.tying
Future Fanatic
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Default 5 N Dime


I found this:

"As to flies tied on larger hooks(4-5/0), the number of turns needed to
provide the optimal torque, 3.24 x 10 to the fourth power negative
centripetal force accelerated toward the shank of the hook, is based in
McClingon’s constant. That constant dictates that one turn is needed
for a size “5” thread (based on the Buford Scale) for each 153 microns
of hook shank(or rotational axis) diameter. For example, a hook shank
that is 500 microns in diameter, would need a minimum of four wraps.
Of course, the material that is to be tied to the shank of the hook
increases the diameter of the wrap and therefore increasing the
centripetal force needed to secure it to the shank of the hook. Thus
the diameter of the material that is to be tied to the hook is to be
calculated using a factor of .5 of McClingon’s constant. It must be
added that if one increases the size of the thread usedby one Buford
unit, the number of wraps decreases by a factor of .347( and increases
at that same rate when one decreases the size of the thread by one
Buford unit)"


--
Future Fanatic

John
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the truth will set you free.
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  #2  
Old October 17th, 2007, 08:21 PM posted to rec.outdoors.fishing.fly.tying
jcstikfish
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Default 5 N Dime


Future Fanatic;96347 Wrote:
I found this:

"As to flies tied on larger hooks(4-5/0), the number of turns needed to
provide the optimal torque, 3.24 x 10 to the fourth power negative
centripetal force accelerated toward the shank of the hook, is based in
McClingon’s constant. That constant dictates that one turn is needed
for a size “5” thread (based on the Buford Scale) for each 153 microns
of hook shank(or rotational axis) diameter. For example, a hook shank
that is 500 microns in diameter, would need a minimum of four wraps.
Of course, the material that is to be tied to the shank of the hook
increases the diameter of the wrap and therefore increasing the
centripetal force needed to secure it to the shank of the hook. Thus
the diameter of the material that is to be tied to the hook is to be
calculated using a factor of .5 of McClingon’s constant. It must be
added that if one increases the size of the thread usedby one Buford
unit, the number of wraps decreases by a factor of .347( and increases
at that same rate when one decreases the size of the thread by one
Buford unit)"


You know,

I never thought of it that way.....but it DOES make a lot of sense!

My lofty take....
Maybe because an odd number has a more organic look or feel to it. Use
four or six wraps when building a robot, but five wraps on a Spey!
~James


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  #3  
Old October 17th, 2007, 10:59 PM posted to rec.outdoors.fishing.fly.tying
rw
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Default 5 N Dime

Future Fanatic wrote:
I found this:

"As to flies tied on larger hooks(4-5/0), the number of turns needed to
provide the optimal torque, 3.24 x 10 to the fourth power negative
centripetal force accelerated toward the shank of the hook, is based in
McClingon’s constant. That constant dictates that one turn is needed
for a size “5” thread (based on the Buford Scale) for each 153 microns
of hook shank(or rotational axis) diameter. For example, a hook shank
that is 500 microns in diameter, would need a minimum of four wraps.
Of course, the material that is to be tied to the shank of the hook
increases the diameter of the wrap and therefore increasing the
centripetal force needed to secure it to the shank of the hook. Thus
the diameter of the material that is to be tied to the hook is to be
calculated using a factor of .5 of McClingon’s constant. It must be
added that if one increases the size of the thread usedby one Buford
unit, the number of wraps decreases by a factor of .347( and increases
at that same rate when one decreases the size of the thread by one
Buford unit)"




Please keep your units standard. Hook shanks are referred to by gauge
(American Wire Gauge, AWG), not by diameter.

Diameters can be calculated by applying the formula:

D(AWG)=.005·92^((36-AWG)/39) inch.

For the 00, 000, 0000 etc. gauges you use -1, -2, -3, which makes more
sense mathematically than "double nought." This means that in American
wire gage every 6 gauge decrease gives a doubling of the wire diameter,
and every 3 gauge decrease doubles the wire cross sectional area.
Similar to dB in signal and power levels.

Conversion to microns is left to the reader.

--
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  #4  
Old October 18th, 2007, 01:06 AM posted to rec.outdoors.fishing.fly.tying
leadhead
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Default 5 N Dime


FF,


NOBODY uses the Buford scale anymore! Your whole formula is based
on ravings of a deranged scientist with a broken slide rule.


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leadhead
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  #5  
Old October 18th, 2007, 01:17 AM posted to rec.outdoors.fishing.fly.tying
DoubleHaul[_8_]
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Default 5 N Dime


How many licks does it take to get to the center of a Tootsie Pop? The
world may never know. :rofl:


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  #6  
Old October 18th, 2007, 02:09 PM posted to rec.outdoors.fishing.fly.tying
Denis Lamy
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Posts: 15
Default 5 N Dime

leadhead a écrit :
FF,


NOBODY uses the Buford scale anymore! Your whole formula is based
on ravings of a deranged scientist with a broken slide rule.


Foghorn Leghorn="on"
Nobody, I say but nobody uses a slide rule anymore...
/Foghorn Leghorn

It's back to the drawing board guys.

BTW, thanks for the chuckle this morning. :-D

--
Hope to read you soon,

Denis
www.uqtr.ca/~lamyd

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  #7  
Old October 18th, 2007, 07:45 PM posted to rec.outdoors.fishing.fly.tying
Future Fanatic[_2_]
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Default 5 N Dime


leadhead;96373 Wrote:
FF,
NOBODY uses the Buford scale anymore! Your whole formula is based on
ravings of a deranged scientist with a broken slide rule.


Did I type Buford Scale???
I was supposed to type Burford Scale.
The Buford Scale has to do with wind strength.
Everyone knows that the BURFORD Scale has to do with thread diameters.
Clyde Burford was the husband of none other than the Issac Singer's
oldest daughter. He spent much of his time working with thread and
developed the "Burford Scale".
Sorry for the confusion.


--
Future Fanatic

John
Transparency is good and
the truth will set you free.
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  #8  
Old October 19th, 2007, 02:38 PM posted to rec.outdoors.fishing.fly.tying
leadhead[_2_]
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Default 5 N Dime


FF,


Of course, using the Burford scale brings everything together. I always
consult his charts and tables before starting any thread or rib wraps.
His works on dubbing are also fasinating, yet sadly, unfinished.


leadhead


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  #9  
Old October 19th, 2007, 04:05 PM posted to rec.outdoors.fishing.fly.tying
AKSkim[_5_]
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Default 5 N Dime


Future Fanatic;96416 Wrote:
The Buford Scale has to do with wind strength.


FYI-
*Beaufort Scale* for wind and sea state.


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  #10  
Old October 19th, 2007, 05:03 PM posted to rec.outdoors.fishing.fly.tying
Future Fanatic[_3_]
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Default 5 N Dime


AKSkim;96481 Wrote:
FYI-
*Beaufort Scale* for wind and sea state.


Did type "Buford"!?!?

Of course I meant "Beaufort Scale"...
EVERYONE knows that Beaufort was the Irishman who developed the scale
that bares his name back in the early eighteen hundreds. Of course, he
was an officer in the "British" Navy at the time...

And there is NO truth to the rumor that the scale (1-12) is based on
how many potatoes a certain strength wind can roll across the deck of a
ship in ten seconds... No truth what so ever. I think.


--
Future Fanatic

John
Transparency is good and
the truth will set you free.
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